4x^2+70x+300=750

Solution for 4x^2+70x+300=750 equation:

4x^2+70x+300=750

We move all terms to the left:

4x^2+70x+300-(750)=0

We add all the numbers together, and all the variables

4x^2+70x-450=0

a = 4; b = 70; c = -450;
Δ = b2-4ac
Δ = 702-4·4·(-450)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-110}{2*4}=\frac{-180}{8}
=-22+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+110}{2*4}=\frac{40}{8}
=5
$